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AP EAMCET · Maths · Circle

The perpendicular distance from the point \((1,2)\) to common chord of the circles \(x^2+y^2-2 x+4 y-4=0\) and \(x^2+y^2+4 x-6 y-3=0\) is........ units.

  1. A \(\frac{13}{\sqrt{123}}\)
  2. B \(\frac{13}{\sqrt{136}}\)
  3. C \(\frac{13}{\sqrt{63}}\)
  4. D \(\frac{13}{\sqrt{132}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{13}{\sqrt{136}}\)

Step-by-step Solution

Detailed explanation

Given circle, \(x^2+y^2-2 x+4 y-4=0\) and \(x^2+y^2+4 x-6 y-3=0\) Equation of common chord of circle is \(S_1-S_2=0\) \(\therefore \quad\left(x^2+y^2-2 x+4 y-4\right)\) \(-\left(x^2+y^2+4 x-6 y-3\right)=0\)…