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AP EAMCET · Maths · Continuity and Differentiability

The value of k (k>0), for which the function fx=ex-14sinx2k2log1+x22, where x0 and f(0)=8, is continuous at x=0, is

  1. A 1
  2. B 4
  3. C 2
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

Here, we can know for continuity, limx→0fx=8 ⇒limx→0ex-14sinx2k2log1+x22=8 Now, limx→0ex-14sinx2k2log1+x22=limx→0ex-1x4sinx2k2x2×log1+x22x2 (dividing x4, to the numerator and denominator)…