AP EAMCET · Maths · Permutation Combination
The number of ways of arranging the letters of the word BANANA so that the two Ns do not come together, is
- A \(60\)
- B \(80\)
- C \(40\)
- D \(120\)
Answer & Solution
Correct Answer
(C) \(40\)
Step-by-step Solution
Detailed explanation
Total arrangements = \( \frac{6!}{3!2!} = \frac{720}{12} = 60 \) Treat NN as one unit. Arrangements with Ns together = \( \frac{5!}{3!1!} = \frac{120}{6} = 20 \) Arrangements with Ns not together = \( 60 - 20 = 40 \)
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