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AP EAMCET · Maths · Straight Lines

A straight line 4x+y-1=0 through the point A(2,-7) meets the line BC whose equation is 3x-4y+1=0 at the point B. Then the equation of the line AC such that AB=AC, is

  1. A 89x-52y-162=0
  2. B 52x+89y+519=0
  3. C 4x-y-15=0
  4. D 4x+3y+13=0
Verified Solution

Answer & Solution

Correct Answer

(B) 52x+89y+519=0

Step-by-step Solution

Detailed explanation

The equation of line given as 4x+y-1=0, 3x-4y+1=0. The slopes of line are m1=-4 and m2=34. Triangle ABC is an isosceles; AB=AC. AB and AC both pass through points (2,-7). The slope is, m3=-4-341+(-4)34=198 The required equation of line AC is, y+7x-2=34-1981+34×198…