AP EAMCET · Maths · Properties of Triangles
In \(\triangle \mathrm{ABC}\), if \((\sin \mathrm{A}+\sin \mathrm{B})(\sin \mathrm{A}-\sin \mathrm{B})=\sin \mathrm{C}(\sin \mathrm{B}\) \(+\sin C\) ), then \(\angle A=\)
- A \(60^{\circ}\)
- B \(30^{\circ}\)
- C \(150^{\circ}\)
- D \(120^{\circ}\)
Answer & Solution
Correct Answer
(D) \(120^{\circ}\)
Step-by-step Solution
Detailed explanation
Sine rule is \[ \Rightarrow \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=k \] Then \(\sin \mathrm{A}=\mathrm{ak}, \sin \mathrm{B}=\mathrm{bk}, \sin \mathrm{C}=\mathrm{ck}\)…
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