AP EAMCET · Maths · Circle
From a point \(P(0, b)\) two tangents are drawn to the circle \(x^2+y^2=16\) and these two tangents intersect \(X\)-axis is two points \(A\) and \(B\). If the area of \(\triangle P A B\) is minimum, then the equation of its circumcircle is
- A \(x^2+y^2=16 \sqrt{2}\)
- B \(x^2+y^2=64\)
- C \(x^2+y^2=32\)
- D \(x^2+y^2=4 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2=32\)
Step-by-step Solution
Detailed explanation
Equation of pair of tangents from point \((0, b)\) drawn to the circle \(x^2+y^2=16\) is For point \(A\) and \(B\), put \(y=0\), then we are getting…
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