AP EAMCET · Maths · Circle
The number of common tangents to the circles \(x^2+y^2+4 x-6 y-12=0\) and \(x^2+y^2-8 x+10 y+5=0\) is
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Equation of given circles \[ \begin{array}{r} S_1: x^2+y^2+4 x-6 y-12=0 \\ \text { and } S_2: x^2+y^2-8 x+10 y+5=0 \end{array} \] \(\because\) Centre of \(S_1\) is \(C_1(-2,3)\) and radius of \(S_1\) is \(r_1=5\) and centre of \(S_2\) is \(C_2(4,-5)\) and radius of \(S_2\) is…
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