AP EAMCET · Maths · Circle
Suppose a circle passes through \((2,2)\) and \((9,9)\) and touches the \(X\)-axis at \(P\). If \(O\) is the origin, then \(O P\) is equal to
- A \(4\)
- B \(5\)
- C \(6\)
- D \(9\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Since, the circle passes through \(A(2,2)\) and \(B(9,9)\) and it touches on \(X\)-axis at \(P\). \(\therefore \quad O P^2=O A \cdot O B\) ...(i) \(\begin{aligned} & O A=\sqrt{2^2+2^2}=2 \sqrt{2} \\ & O B=\sqrt{9^2+9^2}=9 \sqrt{2}\end{aligned}\)…
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