AP EAMCET · Maths · Straight Lines
Two sides of a rhombus are along the lines \(x-y+1=0\) and \(7 x-y-5=0\). If its diagonals intersect at \((-1,-2)\), then one of the vertices of this rhombus is
- A \((3,16)\)
- B \((-1,-12)\)
- C \(\left(\frac{1}{3}, \frac{-8}{3}\right)\)
- D \((2,9)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{1}{3}, \frac{-8}{3}\right)\)
Step-by-step Solution
Detailed explanation
Given equation of lines of two sides of rhombus are \(x-y+1=0 \& 7 x-y-5=0\) On solving these two equation, we get \((x, y)=(1,2)=\) point of intersection of two sides. So equation of diagonal passing through \((1,2)\) and \((-1,-2)\)…
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