AP EAMCET · Maths · Limits
If \(f(x)=\left\{\begin{array}{ll}3 a x-2 b, & x\gt1 \\ a x+b+1, & x \lt 1\end{array}\right.\) and \(\lim _{x \rightarrow 1} f(x)\) exists, then the relation between \(a\) and \(b\) is
- A \(3 a-2 b=1\)
- B \(2 a-3 b=1\)
- C \(2 a+3 b=1\)
- D \(2 a+3 b=-1\)
Answer & Solution
Correct Answer
(B) \(2 a-3 b=1\)
Step-by-step Solution
Detailed explanation
Given, \(f(x)= \begin{cases}3 a x-2 b, & x\gt1 \\ a x+b+1, & x \lt 1\end{cases}\)…
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