AP EAMCET · Maths · Indefinite Integration
\(\begin{aligned} & \int \frac{d x}{(2 \sin x+\sec x)^4}=A(1+\tan x)^{-5} \\ & +B(1+\tan x)^{-6}+C(1+\tan x)^{-7}+k, \text { then } \\ & A+B+C=\end{aligned}\)
- A \(\frac{-86}{105}\)
- B \(\frac{-1}{105}\)
- C \(\frac{-26}{105}\)
- D \(\frac{-16}{105}\)
Answer & Solution
Correct Answer
(D) \(\frac{-16}{105}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & I=\int \frac{d x}{(2 \sin x+\sec x)^4}=\int \frac{\sec ^4 x}{\left(2 \tan x+\sec ^2 x\right)^4} d x \\ & =\int \frac{\left(1+\tan ^2 x\right)}{(1+\tan x)^8} \sec ^2 x d x\end{aligned}\) Let \(\tan x=t \Rightarrow \sec ^2 x d x=d t\) So,…
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