AP EAMCET · PHYSICS · Motion In Two Dimensions
An object projected upwards from the foot of a tower. The object crosses the top of the tower twice with an interval of 8 s and the object reaches foot after 16 s . The height of the tower is [ \(\mathrm{g}=10 \mathrm{~ms}^{-2}\) ]
- A 220 m
- B 240 m
- C 640 m
- D 80 m
Answer & Solution
Correct Answer
(B) 240 m
Step-by-step Solution
Detailed explanation
During downwârd journey, \(\begin{aligned} & \mathrm{t}_{\mathrm{BC}}=\frac{8}{2}=4 \mathrm{~s} \\ & \mathrm{t}_{\mathrm{AC}}=\frac{16}{2}=8 \mathrm{~s} \end{aligned}\) \(\therefore\) Height of the tower is…
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