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AP EAMCET · Maths · Application of Derivatives

The minimum value of fx=x+4x+2 is

  1. A -1
  2. B -2
  3. C 1
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(D) 2

Step-by-step Solution

Detailed explanation

fx=x+4x+2 For minima, f'x=0 1-4x+22=0 x+22=4⇒x+2=±2⇒x=0,-4 f"x=8x+2-3 At x=0, fx will have minima. i.e. the minimum value f0=2