AP EAMCET · PHYSICS · Current Electricity
A current of 6 A enters one comer P of an equilateral triangle PQR having three wires of resistance \(2 \Omega\) each and leaves by the comer \(R\) as shown in figure. Then the currents \(\mathrm{I}_{\mathrm{I}}\), and \(\mathrm{I}_2\), are respectively
- A \(4 \mathrm{~A}, 2 \mathrm{~A}\)
- B \(3 \mathrm{~A}, 3 \mathrm{~A}\)
- C \(6 \mathrm{~A}, 0\)
- D \(2 \mathrm{~A}, 4 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(2 \mathrm{~A}, 4 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
The equivalent circuit diagram is \(\therefore \mathrm{I}_1=\left(\frac{2}{4+2}\right) \mathrm{I}=\frac{1}{3} \times 6=2 \mathrm{~A}\) \(\mathrm{I}_2=\left(\frac{4}{4+2}\right) \mathrm{I}=\frac{2}{3} \times 6=4 \mathrm{~A}\)
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