AP EAMCET · Maths · Straight Lines
If \(p\) and \(q\) are the \(x\) and \(y\)-intercepts respectively of the line passing through the points \((a \cos \alpha, b \sin \alpha)\) and \((a \cos \beta, b \sin \beta)\), then \(\frac{a^2}{p^2}+\frac{b^2}{q^2}=\)
- A \(\sin ^2\left(\frac{\alpha-\beta}{2}\right)\)
- B \(\cos ^2\left(\frac{\alpha-\beta}{2}\right)\)
- C \(\sec ^2\left(\frac{\alpha-\beta}{2}\right)\)
- D \(\operatorname{cosec}^2\left(\frac{\alpha-\beta}{2}\right)\)
Answer & Solution
Correct Answer
(C) \(\sec ^2\left(\frac{\alpha-\beta}{2}\right)\)
Step-by-step Solution
Detailed explanation
The equation of line is: \(\frac{x}{p}+\frac{y}{q}=1\) Equation (i) passes through \((a \cos \alpha, b \sin \alpha)\) and \((a \cos \beta, b \sin \beta)\). \(\therefore \frac{a \cos \alpha}{p}+\frac{b \sin \alpha}{q}=1...(i)\) and…
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