AP EAMCET · Maths · Straight Lines
The mid-point of the line segment joining the centroid and the orthocentre of the triangle whose vertices are \((a, b),(a, c)\) and \((d, c)\), is
- A \(\left(\frac{5 a+d}{6}, \frac{b+5 c}{6}\right)\)
- B \(\left(\frac{a+5 d}{6}, \frac{5 b+c}{6}\right)\)
- C \((a,c)\)
- D \((0,0)\)
Answer & Solution
Correct Answer
(A) \(\left(\frac{5 a+d}{6}, \frac{b+5 c}{6}\right)\)
Step-by-step Solution
Detailed explanation
The vertices of the triangle are given as \(\mathrm{A}(\mathrm{a}, \mathrm{b}), \mathrm{B}(\mathrm{a}, \mathrm{c})\) and \(\mathrm{C}(\mathrm{d}, \mathrm{c})\) Centroid of \(\triangle \mathrm{ABC}=\left(\frac{a+a+d}{3}, \frac{b+c+c}{3}\right)\)…
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