AP EAMCET · Maths · Properties of Triangles
If \(\alpha, \beta, \gamma\) are the lengths of the tangents from the vertices of a triangle to its incircle. Then
- A \(\alpha+\beta+\gamma=\frac{1}{r^2}(\alpha \beta \gamma)\)
- B \(\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}=r(\alpha \beta \gamma)\)
- C \(\alpha+\beta+\gamma=\frac{1}{r}(\alpha \beta \gamma)\)
- D \(\alpha^2+\beta^2+\gamma^2=\frac{2}{r}(\alpha \beta \gamma)\)
Answer & Solution
Correct Answer
(A) \(\alpha+\beta+\gamma=\frac{1}{r^2}(\alpha \beta \gamma)\)
Step-by-step Solution
Detailed explanation
It is given that \(\alpha, \beta, \gamma\) are the length of tangents from the vertices of a triangle to its incircle. Semi-perimeter of \(\triangle A B C\),…
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