AP EAMCET · PHYSICS · Gravitation
The vector form of universal law of gravitation
- A \(\overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}} \overrightarrow{\mathrm{r}}\)
- B \(\overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}^3} \hat{\mathrm{r}}\)
- C \(\overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}^2} \overrightarrow{\mathrm{r}}\)
- D \(\overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}^3} \overrightarrow{\mathrm{r}}\)
Answer & Solution
Correct Answer
(D) \(\overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}^3} \overrightarrow{\mathrm{r}}\)
Step-by-step Solution
Detailed explanation
Vector form of law of gravitation is given as \[ \overrightarrow{\mathrm{F}}=\mathrm{G} \frac{\mathrm{m}_1 \mathrm{~m}_2}{\mathrm{r}^2} \hat{\mathrm{r}} \] As, \(\hat{r}=\frac{\vec{r}}{r}\)…
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