AP EAMCET · Maths · Statistics
The mean deviation from the mean of the series \((a),(a+d),(a+2 d), \ldots \ldots \ldots . .,(a+2 n d)\) is
- A \(\frac{n(n-1) d}{2 n+1}\)
- B \(\frac{n(n+1) d}{2 n+1}\)
- C \((n(n+1) d)\)
- D \(\frac{n(n+1) d}{2 n}\)
Answer & Solution
Correct Answer
(B) \(\frac{n(n+1) d}{2 n+1}\)
Step-by-step Solution
Detailed explanation
The mean of given series \(a, a+d, a+2 d, \ldots \ldots, a+2 n d\) is \(\frac{\frac{2 n+1}{2}[2 a+(2 n) d]}{2 n+1}=(a+n d)=m\) (let) So, the mean deviation \(=\frac{1}{2 n+1} \sum_{i=1}^{2 n+1}\left|x_i-m\right|\)…
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