AP EAMCET · Maths · Vector Algebra
If \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) are non coplanar vectors, then the point of intersection of the line passing through the points \(2 \mathbf{a}+3 \mathbf{b}-\mathbf{c}, 3 \mathbf{a}+4 \mathbf{b}-2 \mathbf{c}\) with the line joining the points \(\mathbf{a}-2 \mathbf{b}+3 \mathbf{c}\), \(\mathbf{a}-6 \mathbf{b}+6 \mathbf{c}\) is
- A \(\mathbf{a}+\mathbf{b}+\mathbf{c}\)
- B \(\mathbf{a}+2 \mathbf{b}\)
- C \(\mathbf{a}+\mathbf{c}\)
- D \(\frac{\mathbf{a}+2 \mathbf{b}+\mathbf{c}}{2}\)
Answer & Solution
Correct Answer
(B) \(\mathbf{a}+2 \mathbf{b}\)
Step-by-step Solution
Detailed explanation
Let, \(\mathbf{O A}=2 \mathbf{a}+3 \mathbf{b}-\mathbf{c}, \mathbf{O B}=3 \mathbf{a}+4 \mathbf{b}-2 \mathbf{c}\) \[ \mathbf{O C}=\mathbf{a}-2 \mathbf{b}+3 \mathbf{c} \text {, and } \mathbf{O D}=\mathbf{a}-6 \mathbf{b}+6 \mathbf{c} \] The vector equation of line joining the points…
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