AP EAMCET · Maths · Straight Lines
The length of the sides of a triangle are \(13,14 \& 15\). If \(\mathrm{R}\) and \(\mathrm{r}\) respectively denote circumradius and inradius of this triangle, then \(8 \mathrm{R}-\mathrm{r}=\)
- A 41
- B 51
- C 61
- D 71
Answer & Solution
Correct Answer
(C) 61
Step-by-step Solution
Detailed explanation
Given sides of triangle are 13, 14, 15 \[ \text { Circumradius }(R)=\frac{a b c}{4 \Delta} \] Inradius \((\mathrm{r})=\frac{\Delta}{5}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If , thenAP EAMCET 2020 Easy
- In any triangle \(\mathrm{ABC}, a(b \cos C-c \cos B)=\)AP EAMCET 2022 Hard
- The feet of perpendicular from the point \(A(1,0,3)\) to the join of the points \(B(4,7,1)\) and \(C(3,5,3)\) isAP EAMCET 2020 Medium
- The cartesian form of the polar equation \(\theta=\tan ^{-1} 2\) isAP EAMCET 2005 Easy
- \(\cos h^{-1} 2=\)AP EAMCET 2024 Medium
- The general solution of the differential equation \(\left(x \sin \frac{y}{x}\right) d y=\left(y \sin \frac{y}{x}-x\right) d x\) isAP EAMCET 2025 Medium
More PYQs from AP EAMCET
- The standard enthalpy of formation of \(\mathrm{CO}_2(\mathrm{~g})\), \(\mathrm{CaO}(\mathrm{s})\) and \(\mathrm{CaCO}_3(\mathrm{~s})\) are \(-393,-634,-1210 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. If all the substances are in standard state, the standard enthalpy of decomposition of calcium carbonate to \(\mathrm{CaO}(\mathrm{s})\) and \(\mathrm{CO}_2\) (g) (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) isAP EAMCET 2023 Medium
- If one of the lines \(2 x^2-x y+b y^2=0\) passes through the point \((-4,-2)\), then \(b^2=\)AP EAMCET 2020 Easy
- The compound which does not respond to iodoform test isAP EAMCET 2018 Medium
- In the circuit given, the charge on the capacitor is
AP EAMCET 2017 Easy - If \(\bar{a}=2 \bar{i}-\bar{j}+6 \bar{k} ; \bar{b}=\bar{i}-\bar{j}+\bar{k}\) and \(\bar{c}=3 \bar{j}-\bar{k}\), then \(\bar{a} \times \bar{b}+\bar{b} \times \bar{c}+\bar{c} \times \bar{a}=\)AP EAMCET 2025 Medium
- A point mass of \(400 \mathrm{~g}\) executes S.H.M. under a force \(\mathrm{F}=-\left(10 \mathrm{Nm}^{-1}\right) \mathrm{x}\). If it crosses the centre of oscillation with a speed of \(10 \mathrm{~ms}^{-1}\), the amplitude of motion isAP EAMCET 2022 Medium