AP EAMCET · Chemistry · Thermodynamics (C)
The standard enthalpy of formation of \(\mathrm{CO}_2(\mathrm{~g})\), \(\mathrm{CaO}(\mathrm{s})\) and \(\mathrm{CaCO}_3(\mathrm{~s})\) are \(-393,-634,-1210 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. If all the substances are in standard state, the standard enthalpy of decomposition of calcium carbonate to \(\mathrm{CaO}(\mathrm{s})\) and \(\mathrm{CO}_2\) (g) (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) is
- A \(969\)
- B \(183\)
- C \(-969\)
- D \(-183\)
Answer & Solution
Correct Answer
(B) \(183\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CaCO}_3(\mathrm{~s}) \stackrel{\Delta}{\longrightarrow} \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{~g})\)…
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