AP EAMCET · Maths · Pair of Lines
If one of the lines \(2 x^2-x y+b y^2=0\) passes through the point \((-4,-2)\), then \(b^2=\)
- A -6
- B 36
- C 4
- D 16
Answer & Solution
Correct Answer
(B) 36
Step-by-step Solution
Detailed explanation
It is given that one of the lines \(2 x^2-x y+b y^2=0\) passes through the point \((-4,-2)\), so \(\begin{aligned} & 2(-4)^2-(-4)(-2)+b(-2)^2 =0 \\ \Rightarrow & 32-8+4 b=0 \Rightarrow b =-6 \\ \therefore & b^2= 36 \end{aligned}\) Hence, option (b) is correct.
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