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AP EAMCET · Maths · Basic of Mathematics

If x2+5x+7(x-3)3=A(x-3)+B(x-3)2+C(x-3)3 , then 9A-3B+C=

  1. A 2
  2. B 5
  3. C 7
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(C) 7

Step-by-step Solution

Detailed explanation

Given, x2+5x+7(x-3)3=A(x-3)+B(x-3)2+C(x-3)3 x2+5x+7(x-3)3=A(x-3)2+B(x-3)+C(x-3)2 x2+5x+7=A(x-3)2+B(x-3)+C Put x=3 9+15+7=A(0)+B(0)+C⇒c=31 x2+5x+7=A(x2-6x+4)+B(x-3)+C x2+5x+7=Ax2+(B-6)x+9A-3B+C Comparing x1, x2 coefficients & constant coefficients…