AP EAMCET · Maths · Circle
The equation of the tangent to the circle \(x^2+y^2=25\) at \((-3,4)\) is
- A \(4 x-3 y+25=0\)
- B \(x+y-1=0\)
- C \(3 x+4 y=0\)
- D \(3 x-4 y+25=0\)
Answer & Solution
Correct Answer
(D) \(3 x-4 y+25=0\)
Step-by-step Solution
Detailed explanation
Equation of tangent: \(x x_1 + y y_1 = r^2\) Substitute \((x_1, y_1) = (-3,4)\) and \(r^2=25\): \((x)(-3) + (y)(4) = 25\) \(-3x + 4y = 25\) \(3x - 4y + 25 = 0\)
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