AP EAMCET · Maths · Straight Lines
Let \(P=(-1,0), Q=(0,0)\) and \(R=(3,3 \sqrt{3})\) be three points. Then the equation of the bisector of the \(\angle \mathrm{PQR}\) is
- A \(\sqrt{3 x}+y=0\)
- B \(x+\frac{\sqrt{3}}{2} y=0\)
- C \(\frac{-\sqrt{3}}{2} x+y=0\)
- D \(x+\sqrt{3} y=0\)
Answer & Solution
Correct Answer
(A) \(\sqrt{3 x}+y=0\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{P}(-1,0), \mathrm{B}=(0,0), R=(3,3 \sqrt{3})\) Now slope of line \(Q M=\tan \frac{2 \pi}{3}=-\sqrt{3}\) \(\therefore\) Equation of line \(Q M=y-\sqrt{3} x=0 \Rightarrow \sqrt{3} x+y=0\)
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