AP EAMCET · Maths · Circle
If \((\alpha, \beta)\) is the external centre of similitude of the circles \(x^2+y^2=3\) and \(x^2+y^2-2 x+4 y+4=0\), then \(\frac{\beta}{\alpha}=\)
- A \(-3\)
- B \(-2\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(-2\)
Step-by-step Solution
Detailed explanation
C_1=\((0,0)\), R_1=\(\sqrt{3}\) C_2=\((1,-2)\), R_2=\(1\) \(\alpha = \frac{R_1 x_2 - R_2 x_1}{R_1 - R_2} = \frac{\sqrt{3}(1) - 1(0)}{\sqrt{3}-1} = \frac{\sqrt{3}}{\sqrt{3}-1}\)…
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