AP EAMCET · Maths · Three Dimensional Geometry
The equation of the plane through \((4,4,0)\) and perpendicular to the planes \(2 x+y+2 z+3=0\) and \(3 x+3 y+2 z-8=0\) is
- A \(4 x+3 y+3 z=28\)
- B \(4 x-2 y-3 z=8\)
- C \(4 x+2 y+3 z=24\)
- D \(4 x+2 y-3 z=24\)
Answer & Solution
Correct Answer
(B) \(4 x-2 y-3 z=8\)
Step-by-step Solution
Detailed explanation
Let DR's of normal to the plane is \( \). Then, equation plane passing through \((4,4,0)\) \((r-a) . n=0\) \(a(x-4)+b(y-4)+c(z)=0\) Since this plane is \(\perp\) to the given planes. So, we get \[ 2 a+b+2 c=0 \quad \text { and } 3 a+3 b+2 c=0 \] By using cross-multiplication…
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