AP EAMCET · Maths · Indefinite Integration
\(\int\left(\frac{\log x-1}{1+(\log x)^2}\right)^2 d x=\)
- A \(\frac{\log x}{1+(\log x)^2}+c\)
- B \(\frac{x}{x^2+1}+c\)
- C \(\frac{x}{1+(\log x)^2}+c\)
- D \(\frac{-x}{1+(\log x)^2}+c\)
Answer & Solution
Correct Answer
(C) \(\frac{x}{1+(\log x)^2}+c\)
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