AP EAMCET · PHYSICS · Atomic Physics
The total energy of an electron in an orbit of hydrogen atom is E. The potential energy of the electron in the same orbit is
- A E
- B \(\frac{E}{2}\)
- C \(2 \mathrm{E}\)
- D \(3 \mathrm{E}\)
Answer & Solution
Correct Answer
(C) \(2 \mathrm{E}\)
Step-by-step Solution
Detailed explanation
Kinetic energy is given by \(\mathrm{K} . \mathrm{E}=\frac{\mathrm{KZe}^2}{2 \mathrm{r}}\) Potential energy is given by \(\text { P.E }=-\frac{K^2 e^2}{r}\) Total energy \(=\mathrm{K} \cdot \mathrm{E}+\mathrm{P} . \mathrm{E}\)…
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