AP EAMCET · Maths · Probability
A bag contains 4 red and 3 black balls. A second bag contains 2 red and 3 black balls. One bag is selected at random. If from the selected bag, one ball is drawn at random, then the probability that the ball drawn is red, is
- A \(\frac{39}{70}\)
- B \(\frac{41}{70}\)
- C \(\frac{29}{70}\)
- D \(\frac{17}{35}\)
Answer & Solution
Correct Answer
(D) \(\frac{17}{35}\)
Step-by-step Solution
Detailed explanation
A red ball can be drawn in two mutually exclusive ways. (i) Selecting bag I and then drawing a red ball from it. (ii) Selecting bag II and then drawing a red ball from it Let \(E_1^{\prime}, E_2\) and \(A\) denote the events defined as follows…
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