AP EAMCET · Maths · Trigonometric Ratios & Identities
Let \(P(\alpha, \beta)\) and \(Q(\gamma, \delta)\) be two points that lie on the curve \(\tan ^2(x+y)+\cos ^2(x+y)\) \(+y^2+2 y=0\) in the \(X Y\)-plane. If the distance between \(P\) and \(Q\) is \(d\), then \(\cos d=\)
- A 0
- B \((-1)^n, n \in N\)
- C \(\pm \pi\)
- D \(\pm 2 n \pi, n \in N\)
Answer & Solution
Correct Answer
(B) \((-1)^n, n \in N\)
Step-by-step Solution
Detailed explanation
We have, \(\tan ^2(x+y)+\cos ^2(x+y)+y^2+2 y=0\) \[ \begin{aligned} & \Rightarrow \quad \sec ^2(x+y)-1+\cos ^2(x+y)+y^2+2 y=0 \\ & \Rightarrow \quad \sec ^2(x+y)+\cos ^2(x+y)+y^2+2 y+1=2 \end{aligned} \] Now, as minimum value of \(\sec ^2(x+y)+\cos ^2(x+y)\) is 2.…
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