AP EAMCET · Maths · Straight Lines
The area of the triangle formed by the pair of lines \(23 x^2-\) \(48 x y+3 y^2=0\) with the line \(2 x+3 y+5=0\) is
- A \(\frac{1}{13 \sqrt{3}}\)
- B \(\frac{25}{13 \sqrt{3}}\)
- C \(\frac{7}{13 \sqrt{5}}\)
- D \(\frac{9}{25 \sqrt{3}}\)
Answer & Solution
Correct Answer
(B) \(\frac{25}{13 \sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Given the equation \(23 x^2-48 x y+3 y^2=0\) After solving this equation we get two lines…
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