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AP EAMCET · Maths · Three Dimensional Geometry

The equation of the plane in normal form which passes through the points (-2,1,3),(1,1,1) and (2,3,4) is

  1. A 23x+-23y+13z=13
  2. B -23x+23y+-13z=13
  3. C -4173x+11173y+-6173z=1173
  4. D 4173x+-11173y+6173z=1173
Verified Solution

Answer & Solution

Correct Answer

(C) -4173x+11173y+-6173z=1173

Step-by-step Solution

Detailed explanation

It is given that the points, A(-2,1,3), B(1,1,1), C(2,3,4) The position vectors are, AB→=i^+j^+k^--2i^+j^+3k^=3i^-2k^ BC¯=2i^+3j^+4k^-i^+j^+k^=i^+2j^+3k^ The normal of the plane, n→=AB→×BC→ n→=i^j^k˙30-2123 By solving the…