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AP EAMCET · Maths · Straight Lines

Suppose P and Q are the mid points of the sides AB and BC of a triangle where A1,3, B3,7 and C7,15 are vertices. Then the locus of R satisfying AC2+QR2=PR2 is

  1. A 6x+12y=297
  2. B 6x+12y+297=0
  3. C 12x+6y=297
  4. D 12x+6y+297=0
Verified Solution

Answer & Solution

Correct Answer

(A) 6x+12y=297

Step-by-step Solution

Detailed explanation

Given, P and Q are the mid points of the sides AB and BC of a triangle where A1,3, B3,7 and C7,15 are vertices, So, coordinates of P are 3+12,7+32=2,5 and of Q are 3+72,7+152=5,11. Let the coordinates of R be x,y, Then AC2+QR2=PR2 ⇒PR2-QR2=AC2…