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AP EAMCET · Maths · Parabola

If \(L\) is the normal drawn to the parabola \(y^2=8 x\) at the point \(t=\frac{1}{\sqrt{2}}\), then the foot of the perpendicular drawn from the focus of the parabola on to the normal L is

  1. A \((3,2)\)
  2. B \((5, \sqrt{2})\)
  3. C \((0, \sqrt{2})\)
  4. D \((3, \sqrt{2})\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((3, \sqrt{2})\)

Step-by-step Solution

Detailed explanation

\(F=(a,0)=(2,0)\) \(P=(at^2, 2at) = (2(\frac{1}{\sqrt{2}})^2, 2(2)(\frac{1}{\sqrt{2}})) = (1, 2\sqrt{2})\) Normal L: \(y+tx = 2at+at^3\)…
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