AP EAMCET · Maths · Vector Algebra
\(3 \overline{\mathrm{i}}+\overline{\mathrm{j}}+\overline{\mathrm{k}}, 2 \overline{\mathrm{i}}+\overline{\mathrm{k}}, \overline{\mathrm{i}}+5 \overline{\mathrm{j}}\) are the position vectors of three non collinear points \(A, B, C\) respectively. If the perpendicular drawn from \(C\) onto \(\overline{A B}\) meets \(\overline{A B}\) at the point \(a \bar{i}+b \bar{j}+c \bar{k}\), then \(a+b+c=\)
- A \(5\)
- B \(3\)
- C \(7\)
- D \(9\)
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\( \vec{AB} = \vec{B} - \vec{A} = (2\overline{i} + \overline{k}) - (3\overline{i} + \overline{j} + \overline{k}) = -\overline{i} - \overline{j} \)…
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