AP EAMCET · Maths · Trigonometric Equations
Find the general solution of ' \(\sin x+\sin 2 x\) \(+\sin 3 x=\cos x+\cos 2 x+\cos 3 x^{\prime}\)
- A \(2 n \pi+\frac{2 \pi}{3}, \frac{n \pi}{2}+\frac{\pi}{8}, n \in Z\)
- B \(2 n \pi-\frac{2 \pi}{3}, \frac{n \pi}{2}-\frac{\pi}{8}, n \in Z\)
- C \(2 n \pi+\frac{2 \pi}{3}, \frac{n \pi}{2} \pm \frac{\pi}{8}, n \in Z\)
- D \(2 n \pi \pm \frac{2 \pi}{3}, \frac{n \pi}{2}+\frac{\pi}{8}, n \in Z\)
Answer & Solution
Correct Answer
(D) \(2 n \pi \pm \frac{2 \pi}{3}, \frac{n \pi}{2}+\frac{\pi}{8}, n \in Z\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \sin x+\sin 2 x+\sin 3 x=\cos x+\cos 2 x+\cos 3 x \\ & (\sin x+\sin 3 x)+\sin 2 x=(\cos x+\cos 3 x)+\cos 2 x \\ & 2 \sin \left(\frac{4 x}{2}\right) \cdot \cos \left(\frac{2 x}{2}\right)+\sin 2 x=2 \cos \left(\frac{4 x}{2}\right) \cos \left(\frac{2…
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