AP EAMCET · Chemistry · d and f Block Elements

In ruby and emerald, the metal ion(s) present is/are

A $\mathrm{Cr}^{6+}, \mathrm{Mn}^{3+}$
B $\mathrm{Cr}^{3+}$
C $\mathrm{Mn}^{3+}, \mathrm{Co}^{3+}$
D $\mathrm{Co}^{3+}$

Verified Solution

Answer & Solution

Correct Answer

(B) $\mathrm{Cr}^{3+}$

Step-by-step Solution

Detailed explanation

Ruby is $\mathrm{Al}_2 \mathrm{O}_3$ in which red colour is obtained when $\mathrm{Cr}^{3+}$ replaces $\mathrm{Al}^{3+}$ ions in octahedral sites. Emerald is $\mathrm{Be}_3 \mathrm{Al}_2\left(\mathrm{SiO}_3\right)_6$ in which green colour is obtained when…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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From AP EAMCET

Match the following.

List - $I$		List - $II$
$(A)$	Addition polymer	$(I)$	Bakelite
$(B)$	Condensation polymer	$(II)$	$2$ -methyl- $1, 3$ -butadiene
$(C)$	Acrilan	$(III)$	$2, 3$ -dimethyl- $1, 3$ -butadiene
$(D)$	Rubber	$(IV)$	Vinyl cyanide
		$(V)$	Polythene

The correct answer is:

AP EAMCET 2019 Easy

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