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AP EAMCET · Maths · Three Dimensional Geometry

Find the equation of the plane passing through the point (2,1,3) and perpendicular to the planes x-2y+2z+3=0 and 3x-2y+4z-4=0.

  1. A 2xy2z+3=0
  2. B x2y+2z3=0
  3. C 2xy+2z3=0
  4. D 2x+y2z3=0
Verified Solution

Answer & Solution

Correct Answer

(A) 2xy2z+3=0

Step-by-step Solution

Detailed explanation

We can conclude, the normal to the plane S1 i.e. x-2y+2z+3=0 is (say) r1→=i^-2j^+2k^ and the normal to the plane S2 i.e. 3x-2y+4z-4=0 is (say) r2→=3i^-2j^+4k^ So, the normal to the plane S3 (which is perpendicular to the plane S1 and S2) is…
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