AP EAMCET · Maths · Statistics
The mean of the squares of first \(n\) natural numbers is
- A \(\left[\frac{n(n+1)}{2}\right]^2\)
- B \(\frac{2 n^2-3 n+1}{6}\)
- C \(\frac{2 n^2+3 n+1}{6}\)
- D \(\frac{n(n+1)(2 n+1)}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 n^2+3 n+1}{6}\)
Step-by-step Solution
Detailed explanation
First \(n\) natural numbers \[ 1,2,3,4, \ldots, n \] Their squares \(1^2, 2^2, 3^2, \ldots, n^2\) \[ \text { Now mean }=\frac{\text { Sum of observations }}{\text { Total number of observations }} \]…
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