AP EAMCET · Maths · Straight Lines
The equation of a straight line which passes through the point and perpendicular to is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
We know that a line perpendicular to the line ax+by+c=0 is given by bx-ay+k=0. Here, given line xsecθ+ycosecθ=a. So, the perpendicular line is xcosecθ-ysecθ+k=0. The point acos3θ,asin3θ lies on the line…
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