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AP EAMCET · Maths · Straight Lines

The equation of a straight line which passes through the point acos3θ,asin3θ and perpendicular to xsecθ+ycosecθ=a is

  1. A xa+ya=acosθ
  2. B xcosθ-ysinθ=acos2θ
  3. C xcosθ+ysinθ=acos2θ
  4. D xcosθ+ysinθ-acos2θ=1
Verified Solution

Answer & Solution

Correct Answer

(B) xcosθ-ysinθ=acos2θ

Step-by-step Solution

Detailed explanation

We know that a line perpendicular to the line ax+by+c=0 is given by bx-ay+k=0. Here, given line xsecθ+ycosecθ=a. So, the perpendicular line is xcosecθ-ysecθ+k=0. The point acos3θ,asin3θ lies on the line…
From AP EAMCET
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