AP EAMCET · Maths · Circle
The centre of a circle is \((2,-3)\) and the circumference is \(10 \pi\). Then its equation is
- A \(x^2+y^2+4 x+6 y+12=0\)
- B \(x^2+y^2-4 x+6 y+12=0\)
- C \(x^2+y^2-4 x+6 y-12=0\)
- D \(x^2+y^2-4 x-6 y-12=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-4 x+6 y-12=0\)
Step-by-step Solution
Detailed explanation
Let the radius of required circle is ' \(r\) ', so the circumference \(=2 \pi r=10 \pi\) (given) \(\Rightarrow \quad r=5\) and centre of required circle is \((2,-3)\) So, the equation of required circle is…
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