AP EAMCET · Maths · Three Dimensional Geometry
The distance of the plane \(3 x+4 y+5 z+19=0\) from the point \((1,-1,1)\) measured along a line parallel to the line with direction ratios \(2,3,1\) is
- A \(\frac{23}{5 \sqrt{2}}\)
- B \(\frac{\sqrt{71}}{5 \sqrt{2}}\)
- C \(\sqrt{14}\)
- D \(\sqrt{23}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{14}\)
Step-by-step Solution
Detailed explanation
According to given information Equation of lines is passing through \((1,-1,1)\) and having DC's is \((2,3,1)\) \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{1}=r\) Here, \((2 r+1,3 r-1, r+1)\) lie on plane. \(\therefore\) These points satisfy the equation of plane.…
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