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AP EAMCET · Maths · Inverse Trigonometric Functions

If \(\sec ^{-1} \frac{x}{a}-\sec ^{-1} \frac{x}{b}=\sec ^{-1} b \sec ^{-1} a\), then \(x\) is equal to

  1. A \(a b\)
  2. B \(-a b\)
  3. C \(a^2\)
  4. D \(b^2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(a b\)

Step-by-step Solution

Detailed explanation

\(\sec ^{-1}\left(\frac{x}{a}\right)-\sec ^{-1}\left(\frac{x}{b}\right)=\sec ^{-1} b-\sec ^{-1} a\) \(\cos ^{-1}\left(\frac{a}{x}\right)-\cos ^{-1}\left(\frac{b}{x}\right)=\cos ^{-1}\left(\frac{1}{b}\right)-\cos ^{-1}\left(\frac{1}{a}\right)\)…