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AP EAMCET · Maths · Complex Number

If \(z=x-i y\) and \(z^{\frac{1}{3}}=a+i b\), then \(\frac{\left(\frac{x}{a}+\frac{y}{b}\right)}{a^2+b^2}=\)

  1. A -2
  2. B -1
  3. C 1
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) -2

Step-by-step Solution

Detailed explanation

Given, \[ \begin{aligned} z & =x-i y \text { and } z^{\frac{1}{3}}=a+i b \\ z^{1 / 3} & =a+i b \end{aligned} \] Take cube on both sides, we get…