AP EAMCET · Maths · Complex Number
If \(z=x-i y\) and \(z^{\frac{1}{3}}=a+i b\), then \(\frac{\left(\frac{x}{a}+\frac{y}{b}\right)}{a^2+b^2}=\)
- A -2
- B -1
- C 1
- D 2
Answer & Solution
Correct Answer
(A) -2
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} z & =x-i y \text { and } z^{\frac{1}{3}}=a+i b \\ z^{1 / 3} & =a+i b \end{aligned} \] Take cube on both sides, we get…
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