AP EAMCET · Maths · Straight Lines
The distance between the lines \(3 x+4 y=9\) and \(6 x+8 y=15\) is equal to units
- A \(\frac{1}{10}\)
- B \(\frac{3}{10}\)
- C \(\frac{5}{10}\)
- D \(\frac{7}{10}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{10}\)
Step-by-step Solution
Detailed explanation
The distance between given parallel lines \(\begin{aligned} 3 x+4 y-9 & =0 \\ 6 x+8 y-15 & =0 \\ \text{is } \frac{18-15}{\sqrt{36+64}} & =\frac{3}{10} \text { unit } \end{aligned}\) Hence, option (b) is correct.
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