AP EAMCET · Maths · Straight Lines
The value of \(c\) such that the straight line joining the points \((0,3)\) and \((5,-2)\) is tangent to the curve \(y=\frac{c}{x+1}\) is
- A 3
- B 4
- C 5
- D 2
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
Equation of line joining \((0,3)\) and \((5,-2)\) is \(\begin{aligned} & \frac{y-3}{x}=-1 \Rightarrow x+y-3=0 ...(i)\\ & \because y=\frac{c}{x+1} \Rightarrow \frac{d y}{d x}=\frac{-c}{(x+1)^2}=-1 \\ & c=(x+1)^2 \\ & y=x+1 \Rightarrow x-y+1=0...(ii) \end{aligned}\) Solving (i)…
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