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AP EAMCET · Maths · Continuity and Differentiability

If the function f(x), defined below, is continuous on the interval [0,8], then f(x)=x2+ax+b,0x<23x+2,2x42ax+5b,4<x8

  1. A a=3, b=-2
  2. B a=-3, b=2
  3. C a=-3, b=-2
  4. D a=3, b=2
Verified Solution

Answer & Solution

Correct Answer

(A) a=3, b=-2

Step-by-step Solution

Detailed explanation

Given that f(x)=x2+ax+b,0≤x<23x+2,2≤x≤42ax+5b,4<x≤8 Since f(x) is continuous on 0,8 i.e. fx is continuous at x=2 and x=4 L.H.L=f(x)=R.H.L limx→2fx=f(2) limx→2x2+ax+b=3x+2=8 4+2a+b=6+2 or 2a+b=4    (i)....…