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AP EAMCET · Maths · Indefinite Integration

\(\int \frac{x-1}{(x+1) \sqrt{x^3+x^2+x}} d x=\)

  1. A \(2 \tan ^{-1}\left(\sqrt{\frac{1+x+x^2}{x}}\right)+c\)
  2. B \(\tan ^{-1}\left(\sqrt{\frac{1+x+x^2}{x}}\right)+c\)
  3. C \(\tan ^{-1}\left(\sqrt{\frac{x}{1+x+x^2}}\right)+c\)
  4. D \(\tan ^{-1}\left(\sqrt{\frac{1+x^2}{x}}\right)+c\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \tan ^{-1}\left(\sqrt{\frac{1+x+x^2}{x}}\right)+c\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \int \frac{x-1}{(x+1) \sqrt{x^3+x^2+x}} d x \\ & \quad=\int \frac{x^2-1}{(x+1)^2 x \sqrt{1+\frac{1}{x}+x}} d x \\ & \quad=\int \frac{x^2-1}{\left(1+1+\frac{1}{x}+x\right) x^2 \sqrt{1+\frac{1}{x}+x}} d x \\ & \quad=\int…